UMLGraph/umlgraph

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#!/bin/sh
#
# Unix shell script to run UMLGraph on the specified base file name
# For this to work you must adjust the following defintion of
# UMLGRAPH_HOME to point to the directory where UmlGraph.jar is installed.
#
#
UMLGRAPH_HOME=lib
# Obtain a classpath path separator that works for Unix and Cygwin
if expr "$JAVA_HOME" : '.*:' >/dev/null ; then
CPS=';'
else
CPS=':'
fi
if [ x$2 = x ]
then
echo usage: umlgraph base_file_name filetype [umlgraph arguments] 1>&2
echo example: umlgraph MyClass png 1>&2
echo '(The above will convert MyClass.java into MyClass.png)' 1>&2
exit 1
else
BASE=$1
FILETYPE=$2
shift 2
java -classpath "$UMLGRAPH_HOME/UmlGraph.jar${CPS}$JAVA_HOME/lib/tools.jar" \
org.umlgraph.doclet.UmlGraph -package $* -output - $BASE.java |
dot -T$FILETYPE -o$BASE.$FILETYPE
fi