diff --git a/cmc_reid_detector.py b/cmc_reid_detector.py
index 1ea2809..53bef98 100644
--- a/cmc_reid_detector.py
+++ b/cmc_reid_detector.py
@@ -34,6 +34,8 @@ if __name__ == '__main__':
             for path in query_list:
                 distance_dict = {} 
                 parsed_query_id = path.split("_")[1]
+                parsed_query_id = parsed_query_id.split(".")[0]
+                parsed_query_id= int(parsed_query_id)
                 print(parsed_query_id)
                 id_feature = extractidfeature(query_path+path, extractor)
                 query_feature_list.append(id_feature) 
@@ -47,10 +49,11 @@ if __name__ == '__main__':
                     counter += 1
                 matched = sorted(distance_dict.items(), key=lambda x : x[1])    # 按特征距离排序
                 # 储存k从前1到前10名的是否（存在命中的ID）
-                temp_acck = [matched[0][0].split("_")[2]==parsed_query_id]     # ID相同为True，否则False
+                temp_acck = [matched[0][0].split("_")[2].split(".")[0]==parsed_query_id]     # ID相同为True，否则False
                 # 获取前k个acck情况
                 for i in range(1,11):
-                    parsed_detector_id = matched[i][0].split("_")[2]
+                    parsed_detector_id = matched[i][0].split("_")[2].split(".")[0]
+					parsed_detector_id=int(parsed_detector_id)
                     print(parsed_detector_id)# 解析出gallary的ID
                     temp_acck.append(parsed_detector_id==parsed_query_id or temp_acck[i-1])    # or用意是表明如果Acc(k-1)已经为True，那么Acck必然为True（递推）
                 print(temp_acck)